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Configuration = 32
cycles = (10 6 3 8 5)(9 4 1 7 2)

a = 4, b = 7, c = 9
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cycles = (10 8 3 5 7)(9 2)(6)(4 1)

a = 5, b = 7, c = 10
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cycles = (10)(9)(8 6 3)(7 2)(5)(4 1)

a = 1, b = 2, c = 7
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cycles = (10)(9)(8 5 2)(7)(6 1 3)(4)

a = 1, b = 3, c = 6
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cycles = (10)(9)(8 3 5)(7)(6)(4)(2)(1)